(6 – 4t) = 0 5(7 – 3t) – 1 9 July 8, 2019 16 32 64 128 0 5t ^ 6 4/(t ^ 4) 5) 0 4(6 - 4t) = 0 5(7 - 3t) - 1 9 0 4(6 - 4t) = 0 5(7 - 3t) - 1 9 2) 0 4(6 - 4t) = 0 5(7 - 3t) - 1 9 4t−3 37t−504 t minus 3 is greater than 37 t minus 50
