0 2 5 6 1 3 July 8, 2019 16 32 64 128 2 5 x 1 3 0 6 1 0 5 6 4x )= 2 x 3 1 0 3 2 5 6 series 1 0 3 2 5 6 number series Evaluate 5 0 6 1 3 2 Order 6 ‐5 2 0 ‐1 3 from greatest to least value 0 3 x 1 2 5 18 6
