0 4 x 1 2 July 8, 2019 16 32 64 128 0 4 x 1 25 (- 0 4 ) x 1 2 0 3 0 4 х 1 =( 6 25 6х 5 0 4 9 x 2 1 0 4 x 1 6 1 2 3 2 0 4 )= x 2 1 6 0 4 x 1 2 )+ 1 6x =- 2 4 x 1 2 16 0 4 x 2x 1 0 X 4 x 2 1 0 solution 4 0 5 x 9 )=- 2 1 3x 1 4 x 1 2 )= 0 0 5x 4 x 2 1 )( 5x2 2 1 4 0 7 x 2 1 0 8 x 1 1 6 4 2 3
