0 7 0 5 3 July 8, 2019 16 32 64 128 0 7 0 х 5 3 0 2 7 )+ 0 3 5 0 4 6x 7 )= 0 5 3x 7 0 4 6y 7 )= 0 5 3y 7 0 7 5а 1 )- 0 5 1 а 3а 0 6 0 7 x 3 5 0 7 5z 3 )= 5 0 1 0 5z 3m 2 (- 0 7 )+( 4 2m 0 5 0 7 0 9 3 5 X 7 0 5 0 3
