1 2 3 0 5 6
- 3 5 0 6 x 1 2
- 3 5 0 6 х 1 2
- 1 0 5 6 4x )= 2 x 3
- 1 2 1 6y 1 3 0 7 y 5
- 1 2 3 6 x 3 )= 5 8 0 4x
- 3 x 1 )- 2 4 x 0 5 )=- 0 6
- 10x 2 5 0 6x 3 )=- 1
- 1 0 3 2 5 6 series
- A (- 1 2 3 b 5 0 6
- 1 0 3 2 5 6 number series
- This numbering system uses 0 1 2 3 5 6 and 7
- Diberikan angka 0 1 2 3 4 5 dan 6
- 0 3 x 1 2 5 18 6
- Tersedia angka 0 1 2 3 4 5 dan 6
- 0 1 2 3 4 5 under addition modulo 6