1 2 c 1 2 3
- 1×2= 3/4 5 с
- 1 2 c 2 1 2 c 3
- 1 2 c 1 3c
- 1 a 2 1 b 2 1 c 2 3
- 2c 2 1 )( 2c 2 1 )( c 4 3
- 1 1 2 1 2 3 pattern in c
- A 1 2 1 b 2 1 3 c (- 4 7 5
- 1 a 2 1 b 2 1 c 2 3 abc
- 1 1 2 1 2 3 c program
- 2 1 2 c 5 1 3
- 2 1 3 c 2 1 10
- 1 2 6c 2 )=- 3 c 1
- Qquad dfrac 1 2 c 2 3c 1
- A 1 2 b 1 2 3 4 c 5 6
- Solve for x. 1 2 c=2 1 2 c–3