1 2 c 8 4 July 8, 2019 16 32 64 128 C 2 11 8 1 4 Solve 1 2 c 8 4 C 1 2 4 8 16 3c 8 3 1 2 c 4 5c 2 4c 1 c 8 2 4c 1 )+ 7 c 8 )=- 32 1 2 4 8 16 series in c 1 2 4 8 16 series in c using for loop C 410 1 2 x1 8 1 - 2 = 4
