1 2x 2 x 5 0
- 1 7 2x 2 x 0 5 корень из 7 7
- 1 2 x 5 )= 0 2x 6
- 3 2x 1 2 x 2 5 0
- 6 2x 1 2 * 25 x 0 5
- 2 2x 1 5 * 2 x 88 0
- 1 6x x 2 8 0 2x 1 5 0 7
- X 1 )( x 2 )( 2x 5 ≥ 0
- X 4 2x 1 6 x 5 2 0
- 2x 1 )( 3x 2 )( 5 x )= 0
- 2x 1 5 x 2 2 0 7x
- 2x 1 2 x 3 2 5 x 7 x 7 0
- 2 x 5 0 5x 1 2x 4 0 25
- 2x 3 )( 3x 1 2 x 5 ) 0
- The quadratic equation 2x 2 5 x 1 0 has