1 4x 5 13 July 8, 2019 16 32 64 128 5 1 4x )- 2x =- 13 5 x 1 )= 4x 13 5 7x 1 4x 13 5 4x − 1 13 − 9 6 3x 1 4x 5 132 solve for x 3x 1 4x 5 132 2 4x 1 4x 5 =- 13 1 5 20y 4x 13 1 5 20y 4x 13 distributive property 5 x 1 )= 4x 13 given 1 5 13 20x ) - 14 4x