1 5 1 7 2 3 July 8, 2019 16 32 64 128 5 1 7 2 3 4 1 5 2 7 3 8 2x 1 5 3x 1 7 2 2х 1 5 3х 1 7 2 3p 1 5 p 1 )- 2 7 2p 7 1 2 5 1 3 as a fraction 1 1 2 3 5 7 sequence 1 3 5 х 7 1 2 2x 1 3 1 5 7 2 5 1 3 divided by 7 1 2 1 3 5 7 2 n 1 7 х 5 )+ 1 2 3 2х 1 1 5 5x 7 =( 2 3 x 1 5 7 1 2 3 4 as a fraction
