1 5 x 2y )( 2 3 xy July 8, 2019 16 32 64 128 X 2 2y 3 =- 1 and xy 3 5 by substitution method X 2 2y 3 =- 1 and xy 3 5 by elimination method 9 1 5 * x 2y )( 2 3 * xy X+y 2 5+z xy