10 7 5 3 2 July 8, 2019 16 32 64 128 7 3 5 2x 10 6 7 3 5 2x )= 10 5 0 1х 7 10 3 2 7 x 5 )- 3 2x 6 )= 10 27 =( 2x 7 10 3 5 7 10 1 4 x 3 5 2 5 10 5 7 minus 5 2 3 7 10 p 2 5 3 8 Solve 7 10 2 by 5 3 2 10 x 5 3 7 6 2 7 10 blank 3 2 6 5 5 3 x 10 7 2 10-2^ 3 div(7-5) cdot 4 10 3 5 plus 7 2 3 7 5 10 9 x 6 3 2
