12 7 2 1 5 July 8, 2019 16 32 64 128 12 2 x 7 2 4 1 ) = 58 Matthew 2 1-5 7-12 7 12 divided by 1 2 4 5 7 12 5 2 x 1 6 Solve the instance 7 2 1 12 5 of the coin row problem 12 1 2 5 7 of 4 2 3 7 12 5 8 and 1 2 as a set of like fraction is 3 2 5b 7 )= 12 5 1 2b
