15 3 7 5 2 July 8, 2019 16 32 64 128 15 2g 7 3 5 15 2 x 3 7 4 5 2 5 целых 7 15 3 20 7 8y 15 8 3 2y 5 15 2х 8 3 4 6х 7 5 5 3 15 or 7 5 20 15 2x 7 3 5 15 6 7 5 divided by 3 2 3 2b 5 )=- 7 2b 15 3 5 7 8 15 x 31 26 7 5 3 4m 26 15 Let 3 7 11 15 and 2 5 8 11 7 3 5 minus 2 11 15 15 2 x chia 3 7 4 5 2