17 4x 5 2x July 8, 2019 16 32 64 128 17 2x 4x 5 what is x Solve 17 2x 4x 5 Y 4x 5 2x y 17 Y 4x 5 2x y 17 substitution 4x 5 ≥ 2x 17 17 3 3 4x 1 2x 5 17 3 3 4x 1 2x 5 justification 2x 2 4x 17 5 Solve 17 2x 4x 5 x