2 1 2 x 0 5 July 8, 2019 16 32 64 128 X 1 2 )( 2x 5 )= 0 1 2 4 x 2 5 0 3 1 2 0 8 x 2 x 0 5 5x 2 1 x 2 0 1 2 x 5 )= 0 2x 6 1 2 х 5 )= 0 2х 6 1 7 2x 2 x 0 5 корень из 7 7 3 2x 1 2 x 2 5 0 X 2 1 4 )( 2x 2 5 )= 0 X 2 1 2 5x 2 5 0 Log1 2 x 2 0 5x 1 2 2x 1 5 * 2 x 88 0 2 1 x+ 7 1 y − 2 0 5x 2y 12
