2 1 5 0 4 July 8, 2019 16 32 64 128 1 2 3 5 0 4 Тек 1 2 0 5 4 A1 =- 1 2 a 5 0 4 1 2 2х 3 )= 0 5 4х 3 4x 2 1 2x 5 )= 0 X 3 5 1 2 0 4 2 1 0 7x 0 48 3 5 1 2 0 4 х 0 5 Х 1 0 4х 2 5 1 2 5 4х )=- 6 0 8х 1 8 4 2 1 0 5 X 2 5 3x 1 5 4 0 X 4 5 )( x 2 1 5 )= 0 5 5 2 0 4 1 solution pdf 1 2 5 0 45
