2 1 5 3 15 July 8, 2019 16 32 64 128 1 2 3 4 5 to 150 1 5 x 2 3 )= 7 15 3х 1 5 2 4 х 3 )/ 15 1 − 2 5 3 x 15 If 1 5 and 2 10 and 3 15 4 20 1 целая 2 5 3 целых 7 15 1 2 3 4 5 6 to 150 1 2 3 4 5 6 до 150 3 1 5 1 2 3 х 15 2 timothy 1 5 3 15 1 5 3 2 d 15 9 10 d 1/5 ( 3/2d-15= 9/10d) W 3 2 5 1 15 2 3x 5 )- 3 x 1 )= 15 3 1 2 y )= 3 5 15y
