2x 3 5x 7 0 July 8, 2019 16 32 64 128 2x 3 5x 2 3x 7 0 2x 3 5x 2 4x 7 0 0 3 5x 7 )= 3 0 2x 3 2 2 5x 7 )- 6 2x 3 )= 0 2x 3y 4 3 5x 2y 7 0 by substitution method 5x 2x 3 )( x 7 )= 0 Solve 5x 3 )( 2x 7 )= 0 X 3 2x 1 5x 1 4x 7 0
