2x 3y 7 8
- 2x 3y 7 3x 2y 8
- 2x 3y 7 5x 2y 8
- 2x 3y 7 0 3x 2y 8 0
- − 2x 3y 7 5x 8y − 2
- 2x 3y 8 4x 6y 7 by elimination method
- 2x 3y 8 4x 6y 7
- 2x 3y 2 8x 12y 7
- 2x 3y 8 x 4y =- 7
- 5x y 8 2x 3y =- 7
- The two lines 2x 3y 7 8x 12y 1 are
- 2x 3y 7 dan 5x 2y 8
- 8 2x 3y 7 6x 4y
- 2xy 8 2x 3y 7
- 2x 3y 7 0 and 9x 2y 8 0
- 2x 3y 8 4x 6y 7 substitution method