2x 4 )( 3x 5 )= 0
- 4 2x 0 3x 13 5
- X 4 2x 3 3x 2 4x 5 0
- X 4 )( 2x 1 )-( 3x 5 )( 2x 8 )= 0
- 2x 4 3x 2 5 0
- 2x 4 3x 3 8x 2 6x 5 0
- 4 2x 3 7 3x 5 0
- 2x 1 4 )(- 1 5 3x )= 0
- 2x 3y 4 0 3x y 5 0
- 2x 3y 4 0 3x y 5 0 by substitution method
- 2x 3y 4 0 3x 4y 5 0
- 2x 3y 4 0 3x y 5 0 by elimination method
- 4 3x 5 )- 5 2x 6 )= 0
- X 5 )( 3 2x )( 3x 4 )= 0
- 2x y 4 3x 2y 6 x 3y 5 0
- X 5 )( 3 2x )( 3x 4 )= 0 tìm nghiệm nguyên