3 2x 4 5x 7 July 8, 2019 16 32 64 128 X 3 2x 4 5x 7 3 2x 1 4 5x 7 2x 4 3 5x 7 2 3 5x 4 7x 2x 4x 1 2x 4 5x 3 )= 21 7 3x 2 8x 7 6 3 2x 4 5x 2 2 32 2x 3 7x 2 5x 4 2x 4 3x 3 5x 2 7x 11 0 Y 4 2x 7 )/ 5x 3 2x 3y 4 3 5x 2y 7 by substitution method 2x 4 x 3 5x 2 x 7 3 2x 5 )+ 7 5x 4 3 2x 4 5x 3x 7 If x 3 2x 4 5x 7 what is the value of x
