3 4 3 5 1 7 July 8, 2019 16 32 64 128 3 4 5 1 7 8 4 3 5 7 1 2 5 x − 3 3 4 )= 7 1 2 3 7 1 4 x 5 3 7 4x 3 4 5 2x .1 1 3 5 5 7 7 3 4 1 3 х 1 5 31 3 4 2 5 1 7 resultado y procedimiento 4 3 5 7 1 2 as a fraction 4 3 5 7 1 2 en fraccion 3 3 4 divided by 1 5 7 3 1 3 4 5 7 as a mixed number 3 2x 4 3 5 x 1 ) = 10x 7 3 5 7 4 3 1 median
