3 4x 1 5 7 July 8, 2019 16 32 64 128 4x 3 2x 1 5 7 4x 3 3 1 5 7 2 32 3 6x 1 )- 5 4x 7 )= 5x 7 4x 1 )= 5 2 3 14x Y x 5 x 3 4x 1 2 7 differentiation 3 4x 1 )= 5 x 1 )+ 7x 3 4x 1 7x 5 4x 3 3x − 1 5 7 3 4x 9 4 1 7x 5 3 4x 1 )- 5 7 x 3 )- 1 3 1 4x 7 5 8x 7 4x 3 x 1 5 5x 7 Solve 4x 3 2x 1 5 7 3 x 1 )/ 5 7 4x 6 11 4 3 2 4x 1 5 /= 7 2