3 5 c 1 4 July 8, 2019 16 32 64 128 3 5c 1 )= 4 3c 2 A 1 3 b 2 5 c (- 4 7 1×2= 3/4 5 с C 1 2 3 4 5 6 A 1 3 b 5 5 c 4 2 Cho a 1 3 b 2 5 c 4 1 Solve for c 5 2c 3 ) 1 4 8c 12 4 2 c )- 5 1 3 9 12c A 1 3 b 2 5 c (- 4 7 are collinear 4c 3 - 5 or c 8 - 1
