3 7 10 2 5 July 8, 2019 16 32 64 128 3 5y 2 7 10 3 5n 2 7 10 3 5 3 5 x 7 10 2 5 3 7 3z )= 2 10 5z 3 7 3z )+ 2 5z 10 )= 0 Fie proportia 2 3 7 10 5 7 10 p 2 5 3 8 3 5y 2 7 10 linear equations 3 2 2x 5 7 10 Solve 7 10 2 5 3 by 2 7 10 blank 3 2 6 5 3 7 x 28 5 2 10 10-2^ 3 div(7-5) cdot 4 3 5x 1 2 7 10
