3 x 0 4 July 8, 2019 16 32 64 128 3 х 0 4 X 3 4x 0 X 3 49x 0 3 2 x 0 4 3 5 x 0 4 3 6 x 0 4 3 9 x 0 4 3 5 x 0 4 2 1 Х 3 4х 0 2x 3 )( x 4 )= 0 X 3 3x 4 0 X 3 x 4 0 by bisection method 5x 3 )( x 4 )= 0 4x 3 x 4 0 6x 3 )(- x 4 )= 0
