3 x 2 6 2x 5
- 3 2 x )=( 6 5x )+ 2x
- 3 2 x )+ 5 2x 6 5x
- 3 2 x 4 )= 1 2x 6 5
- X 3 5x 2 2x 6 0
- 3x 2 6 2x 3 x 1 2 5
- X 2 6 x 4 2x 5 3
- X 3 5x 2 2x 6 x 1
- 3 2x 5 ≥ 2 x 6
- X 3 2x 2 5x 6 0 теорема виета
- Y x 3 5x 2 2x 6
- 3 x − 6 − 8x − 2 5 2x 1
- 3 x 6 )+ 5 2 x )= 10 4 6 2x
- Express 3 x 2 6 2x 5 as a single fraction
- 3x 5 x 2 6 2x 5 4
- (- x 2 6 )( 2x 2 3x 5