3y 2 y 3 5 4y 2 2y 3 8 July 8, 2019 16 32 64 128 Find the sum 3y 2 y 3 5 )+( 4y 2 4y 2y 3 8 Left 3y 2 + y 3 - 5 right )+ left 4y 2 - 4y 2y 3 + 8 right 3 y - 5 - 2y - 4 = 8
%2B(4y^{2}-4y%2B2y^{3}%2B8)&line2=\\mathrm{Solution:\\:}3y^{3}%2B7y^{2}-4y%2B3)