4 9 2 3 5 July 8, 2019 16 32 64 128 4 9 2 3 5 6 4 9 2 3 5 7 4 9 2 3 5 6 as a fraction X 4 2 9 3 5 x 3x X 4 9 3 2 5 6 4 45 х 9 2 3 5 9 4 1 3 2 5 4 9 x 2 3 1 5 4 9 3 5x 2 4 9 3 5x )( 7x 2 8 )= 0 4 5 1 9 2 3 решение 4 5 8 9 2 3 4 9 3 5х )( 7х 2 8 )= 0 4 5y 9 )-( 6 2 3 1y 4 9 2 5 3 7 ascending order
