4 a 2 3 July 8, 2019 16 32 64 128 4 a 2 )= 32 4 a 2 36 4 a 2 3 )+ 6 A 4 2 3 1 formation A 4 2 3 1 4 a 3 2 5 A 4 3x 2 4 2 3 as an improper fraction 4 2 3 in fraction 4 2 3 7 4 2 3 divided by 7 4 2 3 8 4 2 3 9 4 2 3 1 1 6 4 2 3 x
