4x 1 )( x 3 )= 0
- 4x 1 2 x 0 3
- 4x 5 x 3 4x 2 1 0
- X 4 4x 3 1 0
- X 3 3x 2 4x 1 0
- X 2 1 4x 3 8 0
- 4x 3 2 4 x 1 2 0
- 4x 1 )( x 3 )-( 2x 1 2 0
- 4x 1 )( x 3 )-( x 3 )( 5x 2 )= 0
- X ^ 3 + 4x ^ 2 + 6x - 1 = 0
- 4x 1 3 x 0 the first step in solving this equation is to
- Consider this equation 4x 1 3 x 0
- 4x 1 )( x 5 )/( 2x 10 )( x 3 )= 0
- X 3 4x 1 0 by regula falsi method
- X 3 4x 1 0 rational root theorem
- 2x 1 2 4x 1 x 3 15 0