5 0 6 1 3 2 July 8, 2019 16 32 64 128 3 5 0 6 x 1 2 3 5 0 6 х 1 2 0 6 4x 3 )+ 2 1 x 5 0 6 4х 3 )+ 2 1 х 5 6х 2 х 0 6 )=- 3 1 5 Evaluate 5 0 6 1 3 2 1 0 3 2 5 6 series Order 6 ‐5 2 0 ‐1 3 from greatest to least value 1 0 3 2 5 6 number series 2x 1 3 =- 5 0 6 Inversul numărului rațional a 0 5 1 6 2 3 2 1 5 x 0 6 x 3 25 x 15 18
