5 2 7 4 1 3
- 5 3 5x 2 )= 4 7 3x )+ 1
- 5 3 5x 2 )= 4 7 3x )+ 1 and check the solution
- 5 1 2 2y )= 7 3 4 3y 1
- 6 2 5 x 2 7 x 4 1 3
- 5 1 2 2у )= 7 3 4 3у 1
- 2 4 7 x 1 3 5
- 5 7y 2 3y 4 1 7
- 5 1 7 times 4 2 3
- 2 5x 3 7 1 4 3 7x3 5
- 5 3 5y 2 )= 4 7 3y )+ 1
- 5 3 5x 2 )= 4 7 3x )+ 1 solve
- 4 2 5 times 7 1 3 is what number
- 2 4 7 x 1 3 5 as a fraction