5 y 1 )= 3 3y 4 July 8, 2019 16 32 64 128 6 y 1 3 )= 4 3y 5 5 y 2 3 )- 3 4 3y 1 2 Solve for y 6 y 1 3 )= 4 3y 5 (5y + 4) (1 1y – 3 3) = 0 5 y + 3 y - 1 3 = 1 1