5x 2 x 2 1 3 4x July 8, 2019 16 32 64 128 5x 3 x 2x 2 4 )+( 3x 2 1 4x ∫ _( 1 2 5x 2 x 2 )+ 4x 3 dx 5x 7 x 2 )= 3 2 4x 1 5x 3 4x 2 1 untuk x 2 7 5x 2 x 3 3 1 4x 3 7x 2 1 2 x 4 )= 4x 3 2 5x 4x 2 9x 1 )+( x 2 5x 3 X 3 2 5x x 1 )- 9 4x 2 5 x 5 x 5 x 5 x 5 2x 5 5 x 5 x 5
