5y 4 )( 5y 1 July 8, 2019 16 32 64 128 5y 4 )( 13 5y )= 0 4 5y 1 5y 3 2y 2x 5y 4 7x 5y =- 1 3 5y 2 5 )+ 4 5y 1 16 5y 4 1 5y 5y 5 5y 4 10y 3 4 5y 2 5y 10
