6 3 5 x 2 7 9 July 8, 2019 16 32 64 128 8 4 2 6 4 5 x 3 7 9 1 3 2 9 х 3 5 3 5 x 6 7 9 6 x 7 y 3 5 x 2 y 9 6 X 7 y 3 5 x 2 y 9 6 by substitution method X 7 y 3 5 x 2 y 9 6 by elimination method 1 3x 7 9 )( 6 5 3 2 x )= 0 X 2 3 y =- 5 6 z =- 7 9 Solve x 7 y 3 5 x 2 y 9 6 2 7 x 9 3 6 5 x 8 2 9 10 6 5 x 3 2 7 4 3x y 3 5 6 3y x 2 7 9
