7 1 2 x )- 3 4 2x July 8, 2019 16 32 64 128 7 4 x 3 2x 1 2 as a fraction 3 2x 1 2 x 2 7 4 9 2 3x 7 )+ 3 x 1 )= 4 2x 3 Solve x 1 3 4 2x 1 2 7 3 x 4 )/ 14 2 2x 1 )/ 7 9 2x 7 2 ⋅ ( 7 x − 1 2 ) = ( 5 + 4 3 x ) ⋅ 4