7 1 4 8 1 2 July 8, 2019 16 32 64 128 7 1 4 8 2 9 7 3 4 8 1 2 7 8 1 4 x 1 2 7 1 8 4 2 5 1 7 8 y 4 1 2 Dfrac 7 8 dfrac 1 4 dfrac 1 2 7 1 2 4 1 2 x 8 1 3 7 1 2 divided 4 1 2 5 1 8 (- 7 8 1 целая 1 6 )* 2 4 3 7 х 1 8 3 4 1 2 7 8 1 4 1 2 in fraction 7 8 1 4 1 2 solution Evaluate 7 8 1 4 1 2 7 8 ≥ 1 4 x 1 2 1 4 4x 8 )=- 7 1 2
