7 12 x 1 5 July 8, 2019 16 32 64 128 X 1 )+( 12 7 5x 12 1 x 5 8 1 7 7 12 3 5 x 1 3 5 3 7 x 12 1 4 12 5 x 1 )= 7 3x 2x 13x 7 12 x 1 )+ x 5 7 12 xt 5 x 1 3 14 45 − 12 ≤ x 7 1 5 7 2 x 5 x 12 1 7x 8 30 x 5 12 7 x 1 7 5 4 x 7 12 1 5 3 x 1 5x 12 6x 7 13 x − 7 12 x − 1 x 5
