7 2 4 1 5 3 July 8, 2019 16 32 64 128 2 4 7 x 1 3 5 7 2 3 х )= 4 х 1 )+ 5 2 7 8 х )+ 4 1 6 5 3 4 4 7 3z )+ 1 5 3 5z 2 1 4 7 times 2 3 5 Oblicz 1 4 5 3 2 7 Calcul ( – 4)2 + ( – 5)3 – ( – 1)7 2 4 7 x 1 3 5 as a fraction 2 7 2x 3 4 1 5 Find 4 1 5 7 2 3 3 4 2 5 1 7 resultado y procedimiento 7 2 5 t 3 1 4 7 2 5 2 3x 4 1 2 7 1 2 minus 5 3 4
