7 3 0 5 1 July 8, 2019 16 32 64 128 0 7 3 8 1 5 0 7 5z 3 )= 5 0 1 0 5z 0 3 7 2 x 1 5 0 7 3 1 2 5 7 10 5 у 0 3 3х 7 3 5х 11 5 0 3 0 5 7 9 1 7 10 5 z 0 3 Is 7 3 0 1 5 a sequence 7 4 3 5 0 1 7 3 11 0 5 7 * 3 * 11 * 0 * 5 is equal to Mediana liczb 3 0 5 1 7 Arrange in ascending order 7 0 3 5 10 7 5 1 0 6 3
