C 5 7 3 July 8, 2019 16 32 64 128 C 5 14 =- 3 7 3c 5 c )- 2c 3c 7 C 7 h 5 n 3 o 6 C 5 2 d 7 3 5 7 c 3 )= 1 5 7 c )= 32 C 3 7 5 1 2 C 1 3 5 7 99 C 1 3 5 7 9 C 7 3 ) r 5 Solve for c. 5 7 (x+3)=1 C = 2 3 5 7 7 3c 5 c 4 c 5 )+ 4c 7 c 3
