F x sqrt x 2 5
- F x sqrt x 2 5x 6
- F x )= sqrt x 2 )- 5x 6 find the domain and range
- Дана функция f x )= корень x 2 6x 5
- F x )= ln sqrt x 2 5x 24 )- x 2
- If f x )= 2x 2 5 sqrt x 2 the domain
- The range of the function f x )=- sqrt (- x 2 )- 6x 5 is
- If f x )= 2x 2 5 sqrt x 2
- F(x) = sqrt(2 - 5x)
- F(x) = sqrt(5 - x)
- F(x) = sqrt(2x - 5)