First 3 terms of ap are 3y 1 3y 5 5y 1 July 8, 2019 16 32 64 128 4. the first three terms of a.p. are (3y-1) (3y + 5) and (5y + 1). then find y The first 3 terms of an ap are 3y-1 3y+5 and 5y+1 then y is equal to 1. the first three terms of a.p. are (3y – 1) (3y + 5) and (5y + 1). then find the value of y
