K 2 3k 1 July 8, 2019 16 32 64 128 K 2 3k 13 15 K 2 3k 18 0 K 2 3k 10 K 2 3k 18 K 2 3k 10 0 4 k 2 )- 3k 12 Factor k 2 3k 10 2 k 4 )- 3k 14 5k 3 k 2 3k 11 5 k 2 10 3k 9 K 3 3k 2 3k 1 4 k 2 )- 3k ≤ 12 Solve 5 k 2 10 3k 9 1 3 2 k 13 3k 1 2k k 2 =- 3k