P 2 3 1 July 8, 2019 16 32 64 128 P 2 3 11 P 2 3 10 2 p 3 12 2 p 3 13 2 p 3 15 P 3 2 1 4 5 p 3 )- 2 1 2p P = 2 3 5 7 11 P 2 5 rt 1 3 rs st P 1 2 3 4 5 P 1 2 3 4 5 6 P 1 2 3 5 P c )=- 20 c 3 2 180 P 3 3p 2 16p 48 P 1 3 nmv 2 формула