P 2 3 4 July 8, 2019 16 32 64 128 P = 2 3 4 5 P 2 4p 3 P 1 2 3 4 P 1 2 3 4 5 P 1 2 3 4 5 6 P 3 2 2p 4 P x )= x 2 4x 3 3 4 p 2 )= 4 1 8 Punkt p 2 3 4 nalezy do hiperboli Punkt p 2 3 4 nalezy do hiperboli y a x P 2 4p 3 0 P 3 2 48 P 2 )= 80 3 4 t 2 p 4r 3 4p 2r 2 p 4 )+ 3 2p 1
