R 4 1 5 r 2 July 8, 2019 16 32 64 128 5 r 1 )= 2 r 4 )- 6 Solve for r r 4 1 5 r 2 5 r 1 )+ 4 r 2 )= 75 2 r 1 4 r 5 7 2 r 1 4 r 5 7 standard form 5 1 2 r 3 4 r 10 2 r 5 )- 4 r 1 )= 32 R 4 2 1 R 4 1 3 R=4 5
